sci.physics.relativity

"David" wrote in message
news:ajn7e3dsff7rlah716s5rh6md692tko8i6@ ...
: Let there be a line of N planets, all at rest, spanning a length of
: many light-years along the x-axis. Let N be a very large number. Call
: this the rest frame.
:
: Let there be a moving frame with velocity V along the x-axis. Let V
: almost be equal to c, such that the span of N planets, as measured in
: the moving frame, measures less than the length of a brick that has
: zero velocity as measured in the moving frame. Now let that brick
: move very slowly in the y-direction along the y-axis (as measured in
: the moving frame) so that it crosses the x-axis at the same time this
: line of planets is also spanning the same x-coordinates. In this
: moving frame, this brick will simultaneously hit each of the N
: planets.
:
: From the point of view of rest frame of the planets, this brick will
: sequentially hit planet after planet as it travels nearly at the speed
: of light. Now let each point on the planet that this brick hits have
: a second brick on the surface at that same impact point that has
: almost the same velocity as the first brick. In other words, these
: two bricks have almost zero relative velocity. We have N planets, so
: we have N bricks that get hit. From the point of view on the surface
: of each planet, there is a collision on each of the planets of two
: almost identical objects (the high speed bricks).
:
: From the point of view of the moving frame, these N collisions happen
: simultaneously (the given information). The moving frame brick hits
: each of these N bricks on the line of planets. The N bricks all have
: almost zero relative velocity with respect to the brick that hits
: them, hence they are not length contracted as measured in the moving
: frame. From the point of view of the moving frame, how can N bricks
: (where N is a very large number) simultaneous span the same length as
: a single brick that has virtually zero relative velocity with respect
: to each of the bricks it hits?

No matter how many different paradoxes you come up with, the
common cause to them all is:

--


'we establish by definition that the "time" required by
light to travel from A to B equals the "time" it requires
to travel from B to A' because I SAY SO and you have to
agree because I'm the great genius, STOOOPID, don't you
dare question it. -- Rabbi Albert Einstein

/Smart/tAB=